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下面是某些企业常见的算法面试试题，现总结如下，仅供学员参考与学习。 1.比较两个字符串如果不等返回True？ 答案：
Java代码 复制代码 package com.test.kaoshi;
public class StringDemo {
private static String a = "abc"; private static String b = "abcg";
public static boolean equalString() { if (a.equals(b)) { return false; } else {
return true; } } public static void main(String[] args) { StringDemo sd = new StringDemo(); System.out.println("主要考察返回Boolean变量和字符串比较使用的方法?+sd.equalString()); } } [java] view plain copy package com.test.kaoshi;
public class StringDemo {
private static String a = "abc"; private static String b = "abcg";
public static boolean equalString() { if (a.equals(b)) { return false; } else {
return true; } } public static void main(String[] args) { StringDemo sd = new StringDemo(); System.out.println("主要考察返回Boolean变量和字符串比较使用的方法?+sd.equalString()); } } 2.随机产生20个字符并且排序？ 答案：
Java代码 复制代码 package com.test.kaoshi;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Random;
import java.util.Set; import java.util.TreeSet;
public class RadomDemo { /** * 随机产生20个字符串并且字符串不能重复 且进行排序 * @param random * @param len * @return */ public Set getChar(){
Set numberSet01 = new HashSet(); Random rdm = new Random(); char ch; while(numberSet01.size()<20){ int rdGet = Math.abs(rdm.nextInt())%26+97;//产生97到122的随机数a-z值 ch=(char)rdGet; numberSet01.add(ch); //Set中是不能放进重复的值的，当它有20个时，就满足你的条件了 } return numberSet01; } public static void main(String[] args) { RadomDemo rd = new RadomDemo(); Set numberSet01=rd.getChar();
Set numberSet = new TreeSet(); numberSet.addAll(numberSet01); for(Iterator it=numberSet01.iterator();it.hasNext();){ System.out.print(it.next()); } System.out.println(); for(Iterator it=numberSet.iterator();it.hasNext();){ System.out.print(it.next()); } } } [java] view plain copy package com.test.kaoshi;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Random; import java.util.Set; import java.util.TreeSet;
public class RadomDemo { /** * 随机产生20个字符串并且字符串不能重复 且进行排序 * @param random * @param len * @return */ public Set getChar(){
Set numberSet01 = new HashSet(); Random rdm = new Random(); char ch; while(numberSet01.size()<20){ int rdGet = Math.abs(rdm.nextInt())%26+97;//产生97到122的随机数a-z值 ch=(char)rdGet; numberSet01.add(ch); //Set中是不能放进重复的值的，当它有20个时，就满足你的条件了 } return numberSet01; } public static void main(String[] args) { RadomDemo rd = new RadomDemo(); Set numberSet01=rd.getChar();
Set numberSet = new TreeSet(); numberSet.addAll(numberSet01); for(Iterator it=numberSet01.iterator();it.hasNext();){ System.out.print(it.next()); } System.out.println(); for(Iterator it=numberSet.iterator();it.hasNext();){ System.out.print(it.next()); } } } 3.50个人围成一圈数到三和三的倍数时出圈，问剩下的人是谁？在原来的位置是多少？ 答案：
Java代码 复制代码 package com.test.kaoshi;
import java.util.Iterator;
import java.util.LinkedList;
public class YouXi { public static int removeNM(int n, int m) { LinkedList ll = new LinkedList(); for (int i = 0; i < n; i++) ll.add(new Integer(i + 1)); int removed = -1; while (ll.size() > 1) { removed = (removed + m) % ll.size(); ll.remove(removed--); } return ((Integer) ll.get(0)).intValue(); }
public static void main(String[] args) { System.out.println(removeNM(50, 3)); } } （责任编辑：职场达人） |
